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Pips October 12, 2026 answer — October 12, 2026

Monday, Oct 12, 2026

The Pips October 12, 2026 answer for October 12, 2026, with the full solution and how it fits together. Looking for the current puzzle? See nyt pips answers today.

Sukie
Written by Sukie
Published

Monday, October 12, 2026 · edited by Ian Livengood

Easy 5 · Medium 8 · Hard 16 dominoes. The hard board has 30 regions and 0 doubles.

Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.

Easy Pips answer (5 dominoes · by Ian Livengood)

Easy Pips for October 12, 2026, solved3=>8>4=<3

Where each domino goes

  1. 2–4: 2 on R2C2, 4 on R2C3
  2. 5–5: 5 on R1C3, 5 on R1C4
  3. 2–0: 2 on R3C3, 0 on R3C4
  4. 6–2: 6 on R3C1, 2 on R3C2
  5. 3–2: 3 on R1C1, 2 on R1C2

Every region, checked

  • R1C1 (must total 3): 3
  • R1C2, R2C2 (all the same number): 2 + 2
  • R1C3, R1C4 (must total more than 8): 5 + 5 = 10
  • R3C1 (must total more than 4): 6
  • R3C2, R3C3 (all the same number): 2 + 2
  • R3C4 (must total less than 3): 0

Medium Pips answer (8 dominoes · by Ian Livengood)

Medium Pips for October 12, 2026, solved>4<22=57>42

Where each domino goes

  1. 5–4: 5 on R3C6, 4 on R3C5
  2. 2–1: 2 on R2C2, 1 on R2C1
  3. 3–0: 3 on R3C4, 0 on R4C4
  4. 0–4: 0 on R2C3, 4 on R2C4
  5. 2–4: 2 on R3C2, 4 on R3C1
  6. 3–5: 3 on R1C3, 5 on R1C4
  7. 4–4: 4 on R2C5, 4 on R2C6
  8. 3–2: 3 on R3C3, 2 on R4C3

Every region, checked

  • R1C4 (must total more than 4): 5
  • R2C1 (must total less than 2): 1
  • R2C2, R2C3 (must total 2): 2 + 0 = 2
  • R2C4, R2C5, R2C6 (all the same number): 4 + 4 + 4
  • R3C2, R3C3 (must total 5): 2 + 3 = 5
  • R3C4, R3C5 (must total 7): 3 + 4 = 7
  • R3C6 (must total more than 4): 5
  • R4C3, R4C4 (must total 2): 2 + 0 = 2

Hard Pips answer (16 dominoes · by Rodolfo Kurchan)

Hard Pips for October 12, 2026, solved2323110543424120110590350133520

Where each domino goes

  1. 0–1: 0 on R5C3, 1 on R5C4
  2. 0–2: 0 on R3C6, 2 on R3C5
  3. 0–3: 0 on R4C6, 3 on R5C6
  4. 0–4: 0 on R4C3, 4 on R3C3
  5. 0–5: 0 on R6C5, 5 on R5C5
  6. 1–2: 1 on R4C2, 2 on R3C2
  7. 1–3: 1 on R4C1, 3 on R5C1
  8. 1–4: 1 on R2C1, 4 on R3C1
  9. 1–5: 1 on R3C4, 5 on R2C4
  10. 2–3: 2 on R1C4, 3 on R1C5
  11. 2–4: 2 on R1C2, 4 on R2C2
  12. 2–5: 2 on R6C4, 5 on R6C3
  13. 3–4: 3 on R2C6, 4 on R2C5
  14. 3–5: 3 on R6C2, 5 on R5C2
  15. 4–5: 4 on R4C5, 5 on R4C4
  16. 3–6: 3 on R1C3, 6 on R2C3

Every region, checked

  • R1C2 (must total 2): 2
  • R1C3 (must total 3): 3
  • R1C4 (must total 2): 2
  • R1C5 (must total 3): 3
  • R2C1 (must total 1): 1
  • R2C2, R2C3 (must total 10): 4 + 6 = 10
  • R2C4 (must total 5): 5
  • R2C5 (must total 4): 4
  • R2C6 (must total 3): 3
  • R3C1 (must total 4): 4
  • R3C2 (must total 2): 2
  • R3C3 (must total 4): 4
  • R3C4 (must total 1): 1
  • R3C5 (must total 2): 2
  • R3C6 (must total 0): 0
  • R4C1 (must total 1): 1
  • R4C2 (must total 1): 1
  • R4C3 (must total 0): 0
  • R4C4 (must total 5): 5
  • R4C5, R5C5 (must total 9): 4 + 5 = 9
  • R4C6 (must total 0): 0
  • R5C1 (must total 3): 3
  • R5C2 (must total 5): 5
  • R5C3 (must total 0): 0
  • R5C4 (must total 1): 1
  • R5C6 (must total 3): 3
  • R6C2 (must total 3): 3
  • R6C3 (must total 5): 5
  • R6C4 (must total 2): 2
  • R6C5 (must total 0): 0
Place the one-cell regions with a fixed number first: each one tells you a half you must find in the tray.
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