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Pips October 20, 2026 answer — October 20, 2026

Tuesday, Oct 20, 2026

The Pips October 20, 2026 answer for October 20, 2026, with the full solution and how it fits together. Looking for the current puzzle? See nyt pips answers today.

Sukie
Written by Sukie
Published

Tuesday, October 20, 2026 · edited by Ian Livengood

Today's Pips: easy has 5 dominoes, medium has 7 dominoes, hard has 15 dominoes; the hard board is by Rodolfo Kurchan.

Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.

Easy Pips answer (5 dominoes · by Ian Livengood)

Easy Pips for October 20, 2026, solved<27<3==

Where each domino goes

  1. 3–4: 3 on R3C3, 4 on R2C3
  2. 1–1: 1 on R4C2, 1 on R4C3
  3. 4–1: 4 on R5C4, 1 on R5C3
  4. 0–3: 0 on R1C4, 3 on R2C4
  5. 3–1: 3 on R3C2, 1 on R3C1

Every region, checked

  • R1C4 (must total less than 2): 0
  • R2C3, R2C4 (must total 7): 4 + 3 = 7
  • R3C1 (must total less than 3): 1
  • R3C2, R3C3 (all the same number): 3 + 3
  • R4C2, R4C3, R5C3 (all the same number): 1 + 1 + 1

Medium Pips answer (7 dominoes · by Rodolfo Kurchan)

Medium Pips for October 20, 2026, solved56073=>4

Where each domino goes

  1. 2–6: 2 on R1C1, 6 on R1C2
  2. 2–0: 2 on R1C4, 0 on R1C3
  3. 4–3: 4 on R2C4, 3 on R2C3
  4. 0–3: 0 on R3C2, 3 on R3C1
  5. 0–0: 0 on R4C2, 0 on R4C3
  6. 1–3: 1 on R2C2, 3 on R2C1
  7. 3–5: 3 on R3C3, 5 on R3C4

Every region, checked

  • R1C1, R2C1 (must total 5): 2 + 3 = 5
  • R1C2 (must total 6): 6
  • R1C3 (must total 0): 0
  • R2C2, R2C3, R3C3 (must total 7): 1 + 3 + 3 = 7
  • R3C1 (must total 3): 3
  • R3C2, R4C2, R4C3 (all the same number): 0 + 0 + 0
  • R3C4 (must total more than 4): 5

Hard Pips answer (15 dominoes · by Rodolfo Kurchan)

Hard Pips for October 20, 2026, solved3>8>45=>280=>110<23>24305

Where each domino goes

  1. 5–3: 5 on R2C1, 3 on R1C1
  2. 4–1: 4 on R4C1, 1 on R5C1
  3. 6–2: 6 on R2C8, 2 on R1C8
  4. 0–4: 0 on R3C2, 4 on R3C1
  5. 6–5: 6 on R1C5, 5 on R2C5
  6. 0–3: 0 on R9C7, 3 on R8C7
  7. 2–1: 2 on R6C3, 1 on R7C3
  8. 3–4: 3 on R9C5, 4 on R9C4
  9. 2–5: 2 on R7C7, 5 on R6C7
  10. 5–5: 5 on R3C5, 5 on R4C5
  11. 4–5: 4 on R1C2, 5 on R1C3
  12. 3–3: 3 on R8C3, 3 on R9C3
  13. 2–3: 2 on R9C8, 3 on R9C9
  14. 1–1: 1 on R3C8, 1 on R4C8
  15. 1–0: 1 on R4C7, 0 on R4C6

Every region, checked

  • R1C1 (must total 3): 3
  • R1C2, R1C3 (must total more than 8): 4 + 5 = 9
  • R1C5 (must total more than 4): 6
  • R2C1 (must total 5): 5
  • R2C5, R3C5, R4C5 (all the same number): 5 + 5 + 5
  • R2C8 (must total more than 2): 6
  • R3C1, R4C1 (must total 8): 4 + 4 = 8
  • R3C2 (must total 0): 0
  • R3C8, R4C7, R4C8 (all the same number): 1 + 1 + 1
  • R6C3 (must total more than 1): 2
  • R6C7, R7C7, R8C7 (must total 10): 5 + 2 + 3 = 10
  • R7C3 (must total less than 2): 1
  • R8C3 (must total 3): 3
  • R9C3 (must total more than 2): 3
  • R9C4 (must total 4): 4
  • R9C5 (must total 3): 3
  • R9C7 (must total 0): 0
  • R9C8, R9C9 (must total 5): 2 + 3 = 5
Place the one-cell regions with a fixed number first: each one tells you a half you must find in the tray.
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