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Pips November 3, 2026 answer — November 3, 2026

Tuesday, Nov 3, 2026

The Pips November 3, 2026 answer for November 3, 2026, with the full solution and how it fits together. Looking for the current puzzle? See nyt pips answers today.

Sukie
Written by Sukie
Published

Tuesday, November 3, 2026 · edited by Ian Livengood

Today's Pips: easy has 5 dominoes, medium has 7 dominoes, hard has 14 dominoes; the hard board is by Rodolfo Kurchan.

Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.

Easy Pips answer (5 dominoes · by Ian Livengood)

Easy Pips for November 3, 2026, solved>8==

Where each domino goes

  1. 1–2: 1 on R1C1, 2 on R1C2
  2. 2–0: 2 on R1C3, 0 on R1C4
  3. 1–1: 1 on R2C1, 1 on R3C1
  4. 3–3: 3 on R2C4, 3 on R3C4
  5. 0–3: 0 on R2C2, 3 on R2C3

Every region, checked

  • R3C4, R2C4, R2C3 (must total more than 8): 3 + 3 + 3 = 9
  • R1C1, R2C1, R3C1 (all the same number): 1 + 1 + 1
  • R1C2, R1C3 (all the same number): 2 + 2

Medium Pips answer (7 dominoes · by Rodolfo Kurchan)

Medium Pips for November 3, 2026, solved>8>44≠380=

Where each domino goes

  1. 6–3: 6 on R1C1, 3 on R2C1
  2. 4–1: 4 on R1C3, 1 on R2C3
  3. 3–2: 3 on R3C1, 2 on R3C2
  4. 4–4: 4 on R4C4, 4 on R4C5
  5. 3–0: 3 on R2C4, 0 on R3C4
  6. 4–2: 4 on R4C3, 2 on R3C3
  7. 5–5: 5 on R1C2, 5 on R2C2

Every region, checked

  • R1C1, R2C1 (must total more than 8): 6 + 3 = 9
  • R1C2 (must total more than 4): 5
  • R1C3 (must total 4): 4
  • R2C2, R2C3, R2C4 (all different numbers): 5 + 1 + 3
  • R3C1 (must total 3): 3
  • R3C2, R3C3, R4C3 (must total 8): 2 + 2 + 4 = 8
  • R3C4 (must total 0): 0
  • R4C4, R4C5 (all the same number): 4 + 4

Hard Pips answer (14 dominoes · by Rodolfo Kurchan)

Hard Pips for November 3, 2026, solved≠<2>9<200=0622=23<3<5

Where each domino goes

  1. 5–5: 5 on R6C3, 5 on R6C4
  2. 3–3: 3 on R5C6, 3 on R6C6
  3. 3–2: 3 on R5C2, 2 on R4C2
  4. 0–6: 0 on R3C1, 6 on R3C2
  5. 2–0: 2 on R4C1, 0 on R5C1
  6. 0–1: 0 on R2C2, 1 on R1C2
  7. 0–5: 0 on R2C3, 5 on R1C3
  8. 1–5: 1 on R1C5, 5 on R1C4
  9. 2–5: 2 on R1C1, 5 on R2C1
  10. 3–6: 3 on R4C5, 6 on R3C5
  11. 0–4: 0 on R2C5, 4 on R2C6
  12. 1–1: 1 on R5C4, 1 on R5C5
  13. 2–4: 2 on R6C1, 4 on R6C2
  14. 3–4: 3 on R4C6, 4 on R3C6

Every region, checked

  • R1C1, R2C1 (all different numbers): 2 + 5
  • R1C2 (must total less than 2): 1
  • R1C3, R1C4 (must total more than 9): 5 + 5 = 10
  • R1C5 (must total less than 2): 1
  • R2C2 (must total 0): 0
  • R2C3 (must total 0): 0
  • R2C6, R3C6 (all the same number): 4 + 4
  • R3C1 (must total 0): 0
  • R3C2 (must total 6): 6
  • R4C1 (must total 2): 2
  • R4C2 (must total 2): 2
  • R4C5, R4C6, R5C6, R6C6 (all the same number): 3 + 3 + 3 + 3
  • R5C1, R6C1 (must total 2): 0 + 2 = 2
  • R5C2 (must total 3): 3
  • R5C4, R5C5 (must total less than 3): 1 + 1 = 2
  • R6C2 (must total less than 5): 4
Place the one-cell regions with a fixed number first: each one tells you a half you must find in the tray.
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