Sunday, September 27, 2026 · edited by Ian Livengood
Easy 5 · Medium 8 · Hard 12 dominoes. The hard board has 9 regions and 4 doubles.
Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.
Easy Pips answer (5 dominoes · by Ian Livengood)
Where each domino goes
- 1–1: 1 on R3C1, 1 on R4C1
- 4–3: 4 on R3C2, 3 on R2C2
- 6–5: 6 on R3C3, 5 on R3C4
- 0–2: 0 on R4C2, 2 on R4C3
- 3–3: 3 on R1C3, 3 on R2C3
Every region, checked
- R1C3, R2C2, R2C3 (all the same number): 3 + 3 + 3
- R3C1, R4C1, R4C2 (must total 2): 1 + 1 + 0 = 2
- R3C2, R3C3 (must total 10): 4 + 6 = 10
- R3C4 (must total more than 4): 5
Medium Pips answer (8 dominoes · by Ian Livengood)
Where each domino goes
- 6–6: 6 on R3C1, 6 on R3C2
- 4–0: 4 on R4C4, 0 on R4C5
- 5–6: 5 on R2C4, 6 on R2C3
- 4–4: 4 on R4C2, 4 on R4C3
- 3–0: 3 on R1C2, 0 on R1C3
- 0–0: 0 on R1C4, 0 on R1C5
- 1–6: 1 on R3C4, 6 on R3C3
- 0–5: 0 on R3C5, 5 on R3C6
Every region, checked
- R1C3, R1C4, R1C5 (all the same number): 0 + 0 + 0
- R2C3, R3C2, R3C3 (all the same number): 6 + 6 + 6
- R2C4 (must total more than 4): 5
- R3C1 (must total more than 4): 6
- R3C4, R3C5, R4C5 (must total 1): 1 + 0 + 0 = 1
- R3C6 (must total more than 4): 5
- R4C2, R4C3, R4C4 (all the same number): 4 + 4 + 4
Hard Pips answer (12 dominoes · by Rodolfo Kurchan)
Where each domino goes
- 5–0: 5 on R8C3, 0 on R9C3
- 4–3: 4 on R4C5, 3 on R3C5
- 6–2: 6 on R2C3, 2 on R1C3
- 3–1: 3 on R1C1, 1 on R1C2
- 4–4: 4 on R6C3, 4 on R7C3
- 3–3: 3 on R2C1, 3 on R3C1
- 2–2: 2 on R6C4, 2 on R6C5
- 0–0: 0 on R4C1, 0 on R4C2
- 4–2: 4 on R7C6, 2 on R8C6
- 5–6: 5 on R2C6, 6 on R2C5
- 2–3: 2 on R3C3, 3 on R4C3
- 1–0: 1 on R9C4, 0 on R9C5
Every region, checked
- R1C1, R2C1, R3C1 (all the same number): 3 + 3 + 3
- R1C2, R1C3 (must total 3): 1 + 2 = 3
- R2C3, R3C3 (must total 8): 6 + 2 = 8
- R2C5, R2C6, R3C5, R4C5 (all different numbers): 6 + 5 + 3 + 4
- R4C1, R4C2, R4C3 (must total 3): 0 + 0 + 3 = 3
- R6C3, R6C4, R6C5 (must total 8): 4 + 2 + 2 = 8
- R7C3, R8C3 (must total 9): 4 + 5 = 9
- R7C6, R8C6 (must total 6): 4 + 2 = 6
- R9C3, R9C4, R9C5 (must total 1): 0 + 1 + 0 = 1
Place the one-cell regions with a fixed number first: each one tells you a half you must find in the tray.