Monday, September 28, 2026 · edited by Ian Livengood
Today's Pips: easy has 5 dominoes, medium has 7 dominoes, hard has 14 dominoes; the hard board is by Rodolfo Kurchan.
Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.
Easy Pips answer (5 dominoes · by Ian Livengood)
Where each domino goes
- 0–0: 0 on R3C5, 0 on R4C5
- 4–4: 4 on R2C2, 4 on R3C2
- 1–4: 1 on R1C1, 4 on R2C1
- 2–5: 2 on R5C4, 5 on R4C4
- 6–3: 6 on R3C3, 3 on R4C3
Every region, checked
- R1C1 (must total less than 2): 1
- R2C1, R2C2 (all the same number): 4 + 4
- R3C2, R3C3 (must total 10): 4 + 6 = 10
- R3C5, R4C5 (all the same number): 0 + 0
- R4C3, R4C4 (must total 8): 3 + 5 = 8
- R5C4 (must total 2): 2
Medium Pips answer (7 dominoes · by Rodolfo Kurchan)
Where each domino goes
- 4–5: 4 on R3C3, 5 on R4C3
- 4–3: 4 on R1C3, 3 on R2C3
- 0–4: 0 on R2C4, 4 on R3C4
- 1–3: 1 on R4C5, 3 on R4C4
- 5–3: 5 on R2C2, 3 on R3C2
- 4–1: 4 on R1C1, 1 on R1C2
- 3–6: 3 on R5C4, 6 on R5C3
Every region, checked
- R1C1 (must total more than 1): 4
- R1C3 (must total 4): 4
- R2C2, R2C3, R3C2 (must total more than 10): 5 + 3 + 3 = 11
- R2C4 (must total 0): 0
- R3C3, R3C4, R4C3, R5C3 (must total more than 18): 4 + 4 + 5 + 6 = 19
- R4C4, R4C5, R5C4 (must total less than 8): 3 + 1 + 3 = 7
Hard Pips answer (14 dominoes · by Rodolfo Kurchan)
Where each domino goes
- 3–0: 3 on R5C5, 0 on R4C5
- 1–1: 1 on R1C4, 1 on R1C5
- 1–5: 1 on R3C5, 5 on R2C5
- 3–3: 3 on R5C4, 3 on R6C4
- 4–5: 4 on R7C4, 5 on R7C3
- 0–4: 0 on R3C1, 4 on R2C1
- 1–2: 1 on R1C3, 2 on R2C3
- 2–2: 2 on R6C1, 2 on R6C2
- 6–3: 6 on R7C5, 3 on R6C5
- 4–6: 4 on R7C1, 6 on R7C2
- 0–5: 0 on R5C1, 5 on R4C1
- 1–3: 1 on R1C2, 3 on R2C2
- 2–4: 2 on R3C2, 4 on R3C3
- 4–4: 4 on R4C2, 4 on R5C2
Every region, checked
- R1C2, R1C3, R1C4, R1C5 (all the same number): 1 + 1 + 1 + 1
- R2C1, R2C2, R3C1 (must total 7): 4 + 3 + 0 = 7
- R2C3, R3C2, R3C3 (must total 8): 2 + 2 + 4 = 8
- R2C5 (must total more than 4): 5
- R3C5, R4C5 (must total 1): 1 + 0 = 1
- R4C1, R5C1, R6C1 (must total 7): 5 + 0 + 2 = 7
- R4C2 (must total 4): 4
- R5C2 (must total 4): 4
- R5C4, R5C5, R6C4, R6C5 (all the same number): 3 + 3 + 3 + 3
- R6C2 (must total 2): 2
- R7C1, R7C2 (must total more than 9): 4 + 6 = 10
- R7C3, R7C4, R7C5 (must total more than 14): 5 + 4 + 6 = 15
Place the one-cell regions with a fixed number first: each one tells you a half you must find in the tray.