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Pips October 14, 2026 answer — October 14, 2026

Wednesday, Oct 14, 2026

The Pips October 14, 2026 answer for October 14, 2026, with the full solution and how it fits together. Looking for the current puzzle? See nyt pips answers today.

Sukie
Written by Sukie
Published

Wednesday, October 14, 2026 · edited by Ian Livengood

Today's Pips: easy has 5 dominoes, medium has 7 dominoes, hard has 14 dominoes; the hard board is by Rodolfo Kurchan.

Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.

Easy Pips answer (5 dominoes · by Ian Livengood)

Easy Pips for October 14, 2026, solved=9=<6

Where each domino goes

  1. 2–4: 2 on R1C3, 4 on R2C3
  2. 3–3: 3 on R2C1, 3 on R3C1
  3. 1–5: 1 on R3C2, 5 on R2C2
  4. 0–0: 0 on R4C2, 0 on R5C2
  5. 1–1: 1 on R3C3, 1 on R4C3

Every region, checked

  • R2C1, R3C1 (all the same number): 3 + 3
  • R2C2, R2C3 (must total 9): 5 + 4 = 9
  • R3C2, R3C3, R4C3 (all the same number): 1 + 1 + 1
  • R4C2, R5C2 (must total less than 6): 0 + 0 = 0

Medium Pips answer (7 dominoes · by Ian Livengood)

Medium Pips for October 14, 2026, solved>3==<3==8>4

Where each domino goes

  1. 4–4: 4 on R2C5, 4 on R3C5
  2. 3–4: 3 on R1C2, 4 on R1C1
  3. 0–0: 0 on R1C4, 0 on R1C5
  4. 5–1: 5 on R3C3, 1 on R3C2
  5. 0–6: 0 on R3C4, 6 on R2C4
  6. 1–0: 1 on R2C2, 0 on R2C1
  7. 6–3: 6 on R2C3, 3 on R1C3

Every region, checked

  • R1C1 (must total more than 3): 4
  • R1C2, R1C3 (all the same number): 3 + 3
  • R1C4, R1C5 (all the same number): 0 + 0
  • R2C1 (must total less than 3): 0
  • R2C2, R3C2 (all the same number): 1 + 1
  • R2C3, R2C4 (all the same number): 6 + 6
  • R2C5, R3C4, R3C5 (must total 8): 4 + 0 + 4 = 8
  • R3C3 (must total more than 4): 5

Hard Pips answer (14 dominoes · by Rodolfo Kurchan)

Hard Pips for October 14, 2026, solved≠04>7=9=4314<4<3>466

Where each domino goes

  1. 2–6: 2 on R1C8, 6 on R2C8
  2. 4–0: 4 on R1C2, 0 on R1C3
  3. 6–1: 6 on R2C1, 1 on R1C1
  4. 5–6: 5 on R6C6, 6 on R6C7
  5. 1–1: 1 on R3C1, 1 on R4C1
  6. 0–5: 0 on R4C5, 5 on R3C5
  7. 1–3: 1 on R4C2, 3 on R4C3
  8. 2–3: 2 on R6C4, 3 on R6C3
  9. 6–6: 6 on R4C6, 6 on R4C7
  10. 3–3: 3 on R2C3, 3 on R3C3
  11. 0–6: 0 on R6C5, 6 on R7C5
  12. 5–1: 5 on R8C5, 1 on R9C5
  13. 2–4: 2 on R4C8, 4 on R3C8
  14. 4–4: 4 on R1C5, 4 on R2C5

Every region, checked

  • R1C1, R1C2, R2C1 (all different numbers): 1 + 4 + 6
  • R1C3 (must total 0): 0
  • R1C5 (must total 4): 4
  • R1C8, R2C8 (must total more than 7): 2 + 6 = 8
  • R2C3, R3C3 (all the same number): 3 + 3
  • R2C5, R3C5, R4C5 (must total 9): 4 + 5 + 0 = 9
  • R3C1, R4C1, R4C2 (all the same number): 1 + 1 + 1
  • R3C8 (must total 4): 4
  • R4C3 (must total 3): 3
  • R4C6, R4C7, R4C8 (must total 14): 6 + 6 + 2 = 14
  • R6C3 (must total less than 4): 3
  • R6C4, R6C5 (must total less than 3): 2 + 0 = 2
  • R6C6 (must total more than 4): 5
  • R6C7 (must total 6): 6
  • R8C5, R9C5 (must total 6): 5 + 1 = 6
Count the tray before you start: if a value appears once, the region that needs it has only one candidate.
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