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Pips October 15, 2026 answer — October 15, 2026

Thursday, Oct 15, 2026

The Pips October 15, 2026 answer for October 15, 2026, with the full solution and how it fits together. Looking for the current puzzle? See nyt pips answers today.

Sukie
Written by Sukie
Published

Thursday, October 15, 2026 · edited by Ian Livengood

Easy 5 · Medium 8 · Hard 11 dominoes. The hard board has 13 regions and 3 doubles.

Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.

Easy Pips answer (5 dominoes · by Ian Livengood)

Easy Pips for October 15, 2026, solved11010>110>2

Where each domino goes

  1. 5–1: 5 on R2C4, 1 on R1C4
  2. 5–6: 5 on R2C3, 6 on R2C2
  3. 4–2: 4 on R3C2, 2 on R3C1
  4. 3–6: 3 on R4C3, 6 on R3C3
  5. 4–0: 4 on R2C1, 0 on R1C1

Every region, checked

  • R1C4 (must total 1): 1
  • R2C1, R2C2 (must total 10): 4 + 6 = 10
  • R2C3, R2C4 (must total 10): 5 + 5 = 10
  • R3C1 (must total more than 1): 2
  • R3C2, R3C3 (must total 10): 4 + 6 = 10
  • R4C3 (must total more than 2): 3

Medium Pips answer (8 dominoes · by Ian Livengood)

Medium Pips for October 15, 2026, solved<4===<12063

Where each domino goes

  1. 4–2: 4 on R3C1, 2 on R4C1
  2. 3–3: 3 on R2C1, 3 on R2C2
  3. 5–2: 5 on R5C4, 2 on R5C3
  4. 3–4: 3 on R1C3, 4 on R2C3
  5. 1–4: 1 on R5C2, 4 on R5C1
  6. 5–4: 5 on R3C4, 4 on R2C4
  7. 5–5: 5 on R4C3, 5 on R4C4
  8. 4–0: 4 on R3C2, 0 on R3C3

Every region, checked

  • R1C3 (must total less than 4): 3
  • R2C1, R2C2 (all the same number): 3 + 3
  • R2C3, R2C4 (all the same number): 4 + 4
  • R3C1, R3C2 (all the same number): 4 + 4
  • R3C3 (must total less than 1): 0
  • R3C4, R4C3, R4C4, R5C4 (must total 20): 5 + 5 + 5 + 5 = 20
  • R4C1, R5C1 (must total 6): 2 + 4 = 6
  • R5C2, R5C3 (must total 3): 1 + 2 = 3

Hard Pips answer (11 dominoes · by Rodolfo Kurchan)

Hard Pips for October 15, 2026, solved>1>0>3>145=91>9>24

Where each domino goes

  1. 4–6: 4 on R1C8, 6 on R2C8
  2. 4–3: 4 on R4C7, 3 on R3C7
  3. 2–2: 2 on R2C6, 2 on R3C6
  4. 0–5: 0 on R4C8, 5 on R3C8
  5. 4–4: 4 on R3C5, 4 on R4C5
  6. 3–3: 3 on R4C1, 3 on R4C2
  7. 1–4: 1 on R1C1, 4 on R1C2
  8. 2–0: 2 on R2C1, 0 on R3C1
  9. 1–3: 1 on R3C3, 3 on R4C3
  10. 2–4: 2 on R2C5, 4 on R1C5
  11. 3–5: 3 on R1C3, 5 on R2C3

Every region, checked

  • R1C2 (must total more than 1): 4
  • R1C3 (must total more than 0): 3
  • R1C5 (must total more than 3): 4
  • R1C8, R2C8, R3C8 (must total more than 14): 4 + 6 + 5 = 15
  • R2C3 (must total 5): 5
  • R2C5, R2C6 (all the same number): 2 + 2
  • R3C1, R4C1, R4C2, R4C3 (must total 9): 0 + 3 + 3 + 3 = 9
  • R3C3 (must total 1): 1
  • R3C5, R3C6, R4C5 (must total more than 9): 4 + 2 + 4 = 10
  • R3C7 (must total more than 2): 3
  • R4C7, R4C8 (must total 4): 4 + 0 = 4
Place the one-cell regions with a fixed number first: each one tells you a half you must find in the tray.
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