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Pips October 16, 2026 answer — October 16, 2026

Friday, Oct 16, 2026

The Pips October 16, 2026 answer for October 16, 2026, with the full solution and how it fits together. Looking for the current puzzle? See nyt pips answers today.

Sukie
Written by Sukie
Published

Friday, October 16, 2026 · edited by Ian Livengood

Easy 5 · Medium 7 · Hard 14 dominoes. The hard board has 17 regions and 3 doubles.

Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.

Easy Pips answer (5 dominoes · by Ian Livengood)

Easy Pips for October 16, 2026, solved5==>1

Where each domino goes

  1. 3–5: 3 on R2C3, 5 on R3C3
  2. 5–4: 5 on R3C2, 4 on R4C2
  3. 6–4: 6 on R5C3, 4 on R5C2
  4. 4–4: 4 on R4C1, 4 on R5C1
  5. 2–1: 2 on R2C4, 1 on R1C4

Every region, checked

  • R2C3, R2C4 (must total 5): 3 + 2 = 5
  • R3C2, R3C3 (all the same number): 5 + 5
  • R4C1, R4C2, R5C1, R5C2 (all the same number): 4 + 4 + 4 + 4
  • R5C3 (must total more than 1): 6

Medium Pips answer (7 dominoes · by Ian Livengood)

Medium Pips for October 16, 2026, solved<13>21>9>9>3<1

Where each domino goes

  1. 1–5: 1 on R3C1, 5 on R3C2
  2. 5–4: 5 on R3C5, 4 on R2C5
  3. 4–2: 4 on R2C2, 2 on R2C3
  4. 5–5: 5 on R3C3, 5 on R3C4
  5. 0–3: 0 on R4C5, 3 on R4C4
  6. 4–0: 4 on R4C2, 0 on R4C1
  7. 1–0: 1 on R2C4, 0 on R1C4

Every region, checked

  • R1C4 (must total less than 1): 0
  • R2C3, R2C4 (must total 3): 2 + 1 = 3
  • R2C5 (must total more than 2): 4
  • R3C1, R4C1 (must total 1): 1 + 0 = 1
  • R3C2, R3C3 (must total more than 9): 5 + 5 = 10
  • R3C4, R3C5 (must total more than 9): 5 + 5 = 10
  • R4C2 (must total more than 3): 4
  • R4C5 (must total less than 1): 0

Hard Pips answer (14 dominoes · by Rodolfo Kurchan)

Hard Pips for October 16, 2026, solved4=>81625≠1>9=02

Where each domino goes

  1. 5–5: 5 on R5C7, 5 on R6C7
  2. 4–3: 4 on R5C4, 3 on R6C4
  3. 3–2: 3 on R1C7, 2 on R2C7
  4. 0–1: 0 on R6C1, 1 on R5C1
  5. 1–2: 1 on R5C2, 2 on R6C2
  6. 4–5: 4 on R3C7, 5 on R4C7
  7. 2–6: 2 on R3C2, 6 on R2C2
  8. 1–5: 1 on R2C1, 5 on R3C1
  9. 1–1: 1 on R2C5, 1 on R3C5
  10. 0–0: 0 on R1C4, 0 on R2C4
  11. 3–0: 3 on R4C4, 0 on R3C4
  12. 4–1: 4 on R4C2, 1 on R4C1
  13. 3–5: 3 on R3C6, 5 on R4C6
  14. 2–4: 2 on R1C1, 4 on R1C2

Every region, checked

  • R1C2 (must total 4): 4
  • R1C4, R2C4, R3C4 (all the same number): 0 + 0 + 0
  • R1C7, R2C7, R3C7 (must total more than 8): 3 + 2 + 4 = 9
  • R2C1 (must total 1): 1
  • R2C2 (must total 6): 6
  • R2C5, R3C5 (must total 2): 1 + 1 = 2
  • R3C1 (must total 5): 5
  • R3C2, R4C2 (all different numbers): 2 + 4
  • R4C1 (must total 1): 1
  • R4C4, R5C4, R6C4 (must total more than 9): 3 + 4 + 3 = 10
  • R4C6, R4C7, R5C7, R6C7 (all the same number): 5 + 5 + 5 + 5
  • R6C1 (must total 0): 0
  • R6C2 (must total 2): 2
Place the one-cell regions with a fixed number first: each one tells you a half you must find in the tray.
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