Skip to content
HintSheet
Pips · archive

Pips October 17, 2026 answer — October 17, 2026

Saturday, Oct 17, 2026

The Pips October 17, 2026 answer for October 17, 2026, with the full solution and how it fits together. Looking for the current puzzle? See nyt pips answers today.

Sukie
Written by Sukie
Published

Saturday, October 17, 2026 · edited by Ian Livengood

Easy 5 · Medium 7 · Hard 14 dominoes. The hard board has 17 regions and 3 doubles.

Cells are written row then column from the top-left (R1C1). Each domino is read in the Times’ own orientation: its first number on the first cell listed.

Easy Pips answer (5 dominoes · by Ian Livengood)

Easy Pips for October 17, 2026, solved==<1>5

Where each domino goes

  1. 0–0: 0 on R2C4, 0 on R2C5
  2. 6–0: 6 on R3C1, 0 on R3C2
  3. 5–0: 5 on R3C3, 0 on R3C4
  4. 0–1: 0 on R2C2, 1 on R1C2
  5. 2–2: 2 on R1C3, 2 on R1C4

Every region, checked

  • R1C3, R1C4 (all the same number): 2 + 2
  • R2C2, R3C2 (all the same number): 0 + 0
  • R2C4, R2C5, R3C4 (must total less than 1): 0 + 0 + 0 = 0
  • R3C1 (must total more than 5): 6

Medium Pips answer (7 dominoes · by Ian Livengood)

Medium Pips for October 17, 2026, solved<5>82=8<4=2

Where each domino goes

  1. 2–0: 2 on R2C2, 0 on R2C3
  2. 3–6: 3 on R4C1, 6 on R4C2
  3. 5–5: 5 on R3C2, 5 on R3C3
  4. 5–0: 5 on R3C1, 0 on R2C1
  5. 3–3: 3 on R2C4, 3 on R3C4
  6. 6–2: 6 on R4C3, 2 on R4C4
  7. 4–6: 4 on R1C3, 6 on R1C4

Every region, checked

  • R1C3, R2C3 (must total less than 5): 4 + 0 = 4
  • R1C4, R2C4 (must total more than 8): 6 + 3 = 9
  • R2C2 (must total 2): 2
  • R3C1, R3C2 (all the same number): 5 + 5
  • R3C3, R3C4 (must total 8): 5 + 3 = 8
  • R4C1 (must total less than 4): 3
  • R4C2, R4C3 (all the same number): 6 + 6
  • R4C4 (must total 2): 2

Hard Pips answer (14 dominoes · by Rodolfo Kurchan)

Hard Pips for October 17, 2026, solved84≠25305>1505=10=

Where each domino goes

  1. 6–6: 6 on R5C8, 6 on R5C9
  2. 3–5: 3 on R1C3, 5 on R2C3
  3. 3–2: 3 on R3C3, 2 on R4C3
  4. 1–4: 1 on R4C5, 4 on R5C5
  5. 2–0: 2 on R1C6, 0 on R1C7
  6. 6–3: 6 on R5C7, 3 on R6C7
  7. 2–6: 2 on R2C5, 6 on R1C5
  8. 1–6: 1 on R1C2, 6 on R1C1
  9. 0–3: 0 on R3C6, 3 on R3C5
  10. 0–0: 0 on R8C7, 0 on R9C7
  11. 0–5: 0 on R5C1, 5 on R4C1
  12. 4–3: 4 on R7C7, 3 on R7C8
  13. 2–2: 2 on R2C1, 2 on R3C1
  14. 6–5: 6 on R5C2, 5 on R5C3

Every region, checked

  • R1C1, R2C1 (must total 8): 6 + 2 = 8
  • R1C2, R1C3 (must total 4): 1 + 3 = 4
  • R1C5, R2C5, R3C5 (all different numbers): 6 + 2 + 3
  • R1C6, R1C7 (must total 2): 2 + 0 = 2
  • R2C3 (must total 5): 5
  • R3C3 (must total 3): 3
  • R3C6 (must total 0): 0
  • R4C1 (must total 5): 5
  • R4C3 (must total more than 1): 2
  • R4C5, R5C5 (must total 5): 1 + 4 = 5
  • R5C1 (must total 0): 0
  • R5C3 (must total 5): 5
  • R5C7, R5C8, R5C9 (all the same number): 6 + 6 + 6
  • R6C7, R7C7, R7C8 (must total 10): 3 + 4 + 3 = 10
  • R8C7, R9C7 (all the same number): 0 + 0
Place the one-cell regions with a fixed number first: each one tells you a half you must find in the tray.
ShareXRedditWhatsApp